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JEE PHYSICS MCQ: CURRENT ELECTRICITY

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Application +4 | -1
If in a voltaic cell, 5  g\mathrm{5}\,\,\mathrm{g} of zinc is consumed, we will get how many ampere hour (given that ECE\mathrm{ECE} of zinc is 3.38  ×  10−7  kgC−13.38\,\, \times \,\,{10^{ - 7}}\,\,\mathrm{kg}{\mathrm{C}^{ - 1}})
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Correct option: C
4.1
Option C (4.1) is correct because it is calculated by using the formula It=mzIt = \frac{m}{z} and converting the result to ampere-hours.

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