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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
The value of ∫12  [ f  {g  (x)}]−1f′{g  (x)}  g′  (x)  dx\int \nolimits_1^2 \,\,{\left[ {\,f\,\,\left\{ {g\,\,\left( x \right)} \right\}} \right]^{ - 1}}f'\left\{ {g\,\,\left( x \right)} \right\}\,\,g'\,\,\left( x \right)\,\,dx, where g(1)=g(2)g\left( 1 \right) = g\left( 2 \right) is equal to
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Correct option: C
0\mathrm{0}
Option C (0\mathrm{0}) is correct because the integral evaluates to zero since the limits result in the same value due to g(1) = g(2).

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