JEE MATHEMATICS MCQ: CIRCLES

1 Easy

1 of 1

Application +4 | -1

If tangents

P A

and

P B

are drawn to

x^2+y^2=9

from the point

P(4,4)

, then area of

\triangle O A B, O

being the origin, is equal to

View answer and explanation

Correct option: A

\frac{9}{32} \sqrt{207}

sq units

Option A (

\frac{9}{32} \sqrt{207}

sq units) is correct because it is calculated using the length of the perpendicular from the origin to the chord and the length of the chord.

More Questions from CIRCLES

Practice All Chapter MCQs →

{\left( {{\alpha ^2}{x^2} - 2\alpha \mathrm{ }x + 1} \right)^{51}},

x

\left( {\alpha ,2{\alpha ^2}} \right)

{x^2} + {y^2} = 4,

{x^2} + {y^2} - 2x + 4y - 4 = 0

{x^2} + {y^2} = {a^2}

\left( {{x_1},{y_1}} \right)

\quad \alpha, \beta

\gamma

P, Q

x^2+y^2=1

A

(-1,0)

A P, A Q

A R

G P

\cos \alpha / 2, \cos \beta / 2

\cos \gamma / 2

x+y=6

x+2 y=4

x+y=5

x-y=1

9 \pi