NEET UG PHYSICS MCQ: MOTION IN PLANE

1 Easy

1 of 1

Application +4 | -1

The position vector

\bar r

of a particle is given by

\bar r = \left( {A\sin \omega t} \right)i + \left( {A\cos \omega t} \right)j

. If

v

is velocity of particle. Then

\bar v.\,\bar r =

View answer and explanation

Correct option: A

Zero

The horizontal component of a force is given by

F \cos \theta

. Knowing the horizontal component and the angle, we can find the magnitude of the force. Then, the vertical component is

F \sin \theta

, which gives us 87 N, making option C correct.

More Questions from MOTION IN PLANE

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)