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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
The minimum value of the quantity (a2+3a+1)(b2+3b+1)(c2+3c+1)abc\frac{\left(a^2+3 a+1\right)\left(b^2+3 b+1\right)\left(c^2+3 c+1\right)}{a b c}, where a,b,c∈R+a, b, c \in R^{+}, is
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Correct option: B
125
Option B (125) is correct because by applying AM >= GM inequality to each factor, we find the minimum value of the expression.

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