Let $x, y, z \in R^{+}$such that $x+y+z=27$. If maximum value of $x^2 y^3 z^4$ is $\lambda \cdot 6^{10}$, then find the value of $\lambda$.

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1

Let

x, y, z \in R^{+}

such that

x+y+z=27

. If maximum value of

x^2 y^3 z^4

\lambda \cdot 6^{10}

, then find the value of

\lambda

View answer and explanation

Correct option: A

Option A (9) is correct because the maximum value of the expression is found using AM-GM inequality, resulting in

\lambda = 9

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\frac{3}{4}