Neutron decay in free space is given as follows $_0{n^1}{ \to _1}{{\rm{H}}^1} + { - _1}{e^0} + \,\,[\,]$ Then the parenthesis represents a

NEET UG PHYSICS MCQ: NUCLEI

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Neutron decay in free space is given as follows

_0{n^1}{ \to _1}{\mathrm{H}^1} + { - _1}{e^0} + \,\,[\,]

Then the parenthesis represents a

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Correct option: C

Antineutrino

Neutron decay involves the emission of an antineutrino to conserve lepton number.

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\mathrm{216}

\mathrm{125}

{ }_{92} X^{236} \rightarrow{ }_{56} Y^{141}+{ }_{36} Z^{92}+3 R

({R})

{R_0}\; = \mathrm{ }1.3fm

\left({ }_0^1 \mathrm{n}\right)

\left({ }_{92}^{235} \mathrm{U}\right)

1\,\,a.m.u = 931\,\,MeV