JEE CHEMISTRY MCQ: AMINES

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Analyzing +4 | -1

In the given reaction '

\mathrm{A}

' is :-

\left( {\text{A}} \right)\xrightarrow{{{\text{Reduction}}}}\left( {\text{B}} \right)\xrightarrow{{HN{O_2}}}{C_2}{H_5}OH

View answer and explanation

Correct option: A

{CH}_3 {CN}

Option A (

{CH}_3 {CN}

) is correct because reduction of

{CH}_3 {CN}

gives ethylamine, which upon treatment with

HNO_2

gives ethanol.

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\mathrm{Z}

' in the sequence

{{\text{C}}_6}{{\text{H}}_5}{\text{N}}{{\text{H}}_2}\xrightarrow{{{\text{NaN}}{{\text{O}}_2} + {\text{HCl}}}}{\text{X}}\xrightarrow{{{\text{CuCN}}}}{\text{Y}}\xrightarrow{{{{\text{H}}^ + }/{{\text{H}}_2}{\text{O}}}}{\text{Z}}

The primary, secondary and tertiary amines can be distinguished by: Assertion: The main product of reaction of alcoholic silver nitrite and ethyl bromide is nitroethane.

Reason: Silver nitrite is predominantly covalent compound. Hofmann’s bromamide reaction is to convert Gabriel phthalamide synthesis is used for preparation of :- Elements found in explosive are: