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JEE PHYSICS MCQ: OSCILLATIONS

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A mass m is suspended from a spring of length l and force constant K. The frequency of vibration of the mass is f1{f_1}. The spring is cut into two equal parts and the same mass is suspended from one of the parts. The new frequency of vibration of mass is f2{f_2}. Which of the following relations between the frequencies is correct
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Correct option: D
f2=2f1{f_2} = \sqrt 2 {f_1}
Option D (f2=2f1{f_2} = \sqrt 2 {f_1}) is correct because the frequency is proportional to the square root of the spring constant, and cutting the spring in half doubles the spring constant.

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