If $A=\left\{x: x^2-5 x+6=0\right\}, B=\{2,4\}, C=\{4,5\},$ then $A \times(B \cap C)$ is

JEE MATHEMATICS MCQ: SET THEORY

1 Easy

1 of 1

Application +4 | -1

A=\left\{x: x^2-5 x+6=0\right\}, B=\{2,4\}, C=\{4,5\},

then

A \times(B \cap C)

View answer and explanation

Correct option: A

\{(2,4),(3,4)\}

Option A (

\{(2,4),(3,4)\}

) is correct because it represents the Cartesian product of set A and the intersection of sets B and C.

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S

2 a_1 a_2 a_3 \ldots . . a_{2006}

a_1, a_2, a_3, \ldots ., a_{2006}

S

a N=\{a n: n \in N: b N=\{n b: n \in N\}

c N=\{c N: n \in N\}

b N \cap c N=d N

a, b, c \in N

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\}

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n

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40 \%

A, 20 \%

10 \%

C

A

C

4 \%

A

C

2 \%

A