NEET UG CHEMISTRY MCQ: SOLID STATE

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\mathrm{CsBr}

crystal has bcc structure. It has an edge length of 4.3 Å. The shortest interionic distance between

\mathrm{C}{\mathrm{s}^ + }

and

\mathrm{B}{\mathrm{r}^ - }

ions is

View answer and explanation

Correct option: C

3.72A \circ

Option C (

3.72A \circ

) is correct because it's the calculated shortest interionic distance in a BCC structure.

More Questions from SOLID STATE

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\mathrm{C}{\mathrm{s}^ + }

\mathrm{C}{\mathrm{I}^ - }

\;0.181\,\,nm

A

B

A

Y