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NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1
A steel ball of mass 2Β g2 {~g} is thrown downward with velocity 20Β msβˆ’120 {~ms}^{-1} from height 9.4Β m9.4 {~m}. It penetrates into the sand by 60Β cm60 {~cm} and then it stops. The change in mechanical energy of steel ball will be [g=10Β msβˆ’2]\left[g=10 {~ms}^{-2}\right]
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Correct option: B
βˆ’0.6Β J-0.6 {~J}
Option B (-0.6 J) is correct because the change in mechanical energy is the difference between the initial mechanical energy and the final mechanical energy, which is negative due to energy loss from penetration into the sand.

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