NEET UG CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

Option C ($C{H_3}Cl > C{H_2}C{l_2} > CHC{l_3} > CC{l_4}$) is correct because as the symmetry decreases from $CH_3Cl$ to $CHCl_3$, the dipole moment decreases, and $CCl_4$ has zero dipole moment due to its tetrahedral symmetry.