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NEET UG PHYSICS MCQ: SYSTEM OF PARTICLES

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Application +4 | -1
A body is rotating with angular velocity ω=(3i^−4j^−k^)\omega = \left( {3\hat i - 4\hat j - \hat k} \right). The linear velocity of a point having position vector r=(5i^−6j^+6k^)r = \left( {5\hat i - 6\hat j + 6\hat k} \right) is
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Correct option: C
−30i^−23j^+2k^- 30\hat i - 23\hat j + 2\hat k
Option C (−30i^−23j^+2k^- 30\hat i - 23\hat j + 2\hat k) is correct because the linear velocity is calculated using the cross product of angular velocity and position vector: v=ω×rv = \omega \times r.

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