JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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A particle of mass

\text{m}

and charge

\text{q}

travelling with a velocity

\text{v}

along the X-axis enters a uniform electric field

\overrightarrow{\mathrm{E}}

directed along the

\mathrm{Y}

-axis. What will be the trajectory of the particle?

View answer and explanation

Correct option: C

Parabolic

Option C (Parabolic) is correct because the particle experiences constant acceleration in the Y-direction while maintaining constant velocity in the X-direction, resulting in a parabolic trajectory.

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r.

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\left( {{\varepsilon _r} = 8} \right)

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5 \times {10^{ - 2}}

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