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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
In a Δ  ABC,  a,  c  ,  A\Delta \;ABC,\;a,\;c\;,\;A are given and b1,b2{b_1},{b_2} are two values of third side bb such that b=2b1b = 2{b_1}. Then, sin⁡A\sin A is equal to
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Correct option: B
9a2−c28c2\sqrt {\frac{{9{a^2} - {c^2}}}{{8{c^2}}}}
Option B (9a2−c28c2\sqrt {\frac{{9{a^2} - {c^2}}}{{8{c^2}}}}) is correct because it is derived from the quadratic equation formed using the Law of Cosines and the given relationship between the two possible values of the third side.

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