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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1
The total number of ways in which five '++' and three '−-' signs can be arranged in a line such that no two '−-' sign occur together, is
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Correct option: B
20
Option B (20) is correct because arranging 5 '+' signs creates 6 gaps where 3 '-' signs can be placed such that no two '-' signs are together, resulting in 6C3=20{ }^6 C_3 = 20 ways.

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