Question

A compound ‘A’ having the molecular formula ${{\rm{C}}_5}{{\rm{H}}_{12}}{\rm{O}}$, on oxidation gives a compound ‘B’with molecular formula ${{\rm{C}}_5}{{\rm{H}}_{12}}{\rm{O}}$. Compound ‘B’ gave a 2, 4-dinitrophenylhydrazine derivative but did not answer haloform test or silver mirror test. The structure of compound ‘A’

Accepted Answer

$\begin{array}{l} {m{C}}{{m{H}}_3} - {m{C}}{{m{H}}_2} - {m{CH}} - {m{C}}{{m{H}}_2} - {m{C}}{{m{H}}_3}\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;|\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;OH \end{array}$

Answer

${\rm{C}}{{\rm{H}}_3} - {\rm{C}}{{\rm{H}}_2} - {\rm{C}}{{\rm{H}}_2} - {\rm{C}}{{\rm{H}}_2} - {\rm{C}}{{\rm{H}}_2} - {\rm{OH}}$

Answer

$\begin{array}{l} {m{C}}{{m{H}}_3} - {m{C}}{{m{H}}_2} - {m{C}}{{m{H}}_2}{m{CH}} - {m{C}}{{m{H}}_3}\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;|\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;OH \end{array}$

Answer

$\begin{array}{l} {m{C}}{{m{H}}_3} - {m{C}}{{m{H}}_2} - {m{CH}} - {m{C}}{{m{H}}_2} - {m{OH}}\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;|\ \;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;{m{C}}{{m{H}}_3} \end{array}$

NEET UG CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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