NEET UG PHYSICS MCQ: WAVES

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Application +4 | -1

The transverse displacement of string fixed at both ends is given by

y = 0.06\,\sin \left( {\frac{{2\pi x}}{3}} \right)\cos \left( {120\,\pi t} \right)

, where x and y are in metre and t is in second. The length of the string is 1.5m and its mass is

3 \times {10^{ - 2}}\,\,kg

. The tension in the string is equal to

View answer and explanation

Correct option: A

648 N

Option A (648 N) is correct because the tension is calculated using the wave speed derived from the given wave equation and the mass per unit length.

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