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JEE MATHEMATICS MCQ: RATE MEASURE

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If a particle moves according to the law s=6t2−t32s = 6{t^2} - \frac{{{t^3}}}{2}, then the time at which it is momentarily at rest is
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Correct option: C
t=0,  8t = 0,\;8
Option C (t=0,  8t = 0,\;8) is correct because the particle is momentarily at rest when its velocity (first derivative of position) is zero.

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