Skip to main content
Back to ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

JEE CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

1 Medium
1 of 1
Analyzing +4 | -1
Which is the correct order of stability of the following three carbonium ions?
CH2=CHC+H3I,  CH=CCH3∣∣−CH2II,  CH3CH=CHC+H2III\mathop {{\text{C}}{{\text{H}}_2} = {\text{CH}}\mathop {\text{C}}\limits^ + {{\text{H}}_3}}\limits_{\text{I}} ,\,\,\mathop {{\text{CH}} = \mathop {\text{C}}\limits^{\begin{array}{cccccccccccccccccccc} {{\text{C}}{{\text{H}}_3}} \\ {||} \end{array}} - {\text{C}}{{\text{H}}_2}}\limits_{{\text{II}}} ,\,\,\mathop {{\text{C}}{{\text{H}}_3}{\text{CH}} = {\text{CH}}\mathop {\text{C}}\limits^ + {{\text{H}}_2}}\limits_{{\text{III}}}
View answer and explanation
Correct option: C
I ≈\approx III >> II
Option C is correct. Carbocations are stabilized by +I effect and delocalization. I and III are more stable than II due to more delocalization.

More Questions from ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.