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NEET UG PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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Application +4 | -1
The surface tension of a soap solution is 2×10−2Nm−12 \times 10^{-2} \mathrm{Nm}^{-1}. To blow a bubble of radius 1 cm1 \mathrm{~cm}, the work done is
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Correct option: D
16π×10−6 J16 \pi \times 10^{-6} \mathrm{~J}
Option D (16π×10−6 J16 \pi \times 10^{-6} \text{{ J}}) is correct because the work done to blow a soap bubble is calculated by multiplying the surface tension by the change in surface area (which is doubled for a soap bubble).

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