For the reaction, $2{\rm{F}}{{\rm{e}}^{3 + }} + {\rm{S}}{{\rm{n}}^{2 + }} \to 2{\rm{F}}{{\rm{e}}^{2 + }} + {\rm{S}}{{\rm{n}}^{4 + }}$ The normality of ${\rm{SnC}}{{\rm{l}}_2}$ (mol.wt. = 189.7) solution prepared by dissolving 47.5 g in acid solution and diluting with ${{\rm{H}}_2}{\rm{O}}$ to a total of 2.25 litre is :

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

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For the reaction,

2\mathrm{F}{\mathrm{e}^{3 + }} + \mathrm{S}{\mathrm{n}^{2 + }} \to 2\mathrm{F}{\mathrm{e}^{2 + }} + \mathrm{S}{\mathrm{n}^{4 + }}

The normality of

\mathrm{SnC}{\mathrm{l}_2}

(mol.wt. = 189.7) solution prepared by dissolving 47.5 g in acid solution and diluting with

{\mathrm{H}_2}\mathrm{O}

to a total of 2.25 litre is :

View answer and explanation

Correct option: A

0.222

N

Option A (0.222

N

) is correct because the normality is calculated by dividing the given mass by the equivalent weight and the volume of the solution.