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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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Application +4 | -1
From the top of a tower of height 50m, a ball is thrown vertically upwards with a certain velocity. It hits the ground 10 s after it is thrown up. How much time does it take to cover a distance AB where A and B are two points 20m and 40m below the edge of the tower? (g=10ms−2\mathrm{g} = 10\mathrm{m}{\mathrm{s}^{ - 2}})
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Correct option: D
0.4 s
Option D (0.4 s) is correct because it is the time difference between reaching 20m and 40m below the tower, calculated using kinematic equations.

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