In a radioactive material the activity at time ${t_1}$ is ${R_1}$ and at a later time ${t_2}$, it is ${R_2}$. If the decay constant of the material is $\lambda $ , then

${R_1} = {R_2}\left( {{t_2}/{t_1}} \right)$

JEE PHYSICS MCQ: NUCLEI

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Application +4 | -1

In a radioactive material the activity at time

{t_1}

{R_1}

and at a later time

{t_2}

, it is

{R_2}

. If the decay constant of the material is

\lambda

, then

View answer and explanation

Correct option: D

{R_1} = {R_2}

Option A (

{R_1} = {R_2}{e^{ - \lambda \left( {{{{t_1} - {t_2}}}} \right)}}

) is correct because it correctly represents the relationship between activity and time based on the radioactive decay law.