JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

1 Medium

1 of 1

Application +4 | -1

Which transition in the hydrogen atomic spectrum will have the same wavelength as the Balmer transition (i.e.

\mathrm{n}=4

\mathrm{n}=2

) of

\mathrm{He}^{+}

spectrum

View answer and explanation

Correct option: D

\mathrm{n}=2

\mathrm{n}=1

The correct answer is

\mathrm{n}=2

\mathrm{n}=1

because the wavelength of the Balmer transition (n=4 to n=2) of

\mathrm{He}^{+}

is equal to the wavelength of the transition from n=2 to n=1 in hydrogen.

More Questions from STRUCTURE OF ATOM

Practice All Chapter MCQs →

n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.