If $\left[ {\begin{array}{*{20}{c}} 2&{ - 1}&3\\ 1&3&{ - 1}\\ 3&2&1 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} x\\ y\\ z \end{array}} \right] = \left[ {\begin{array}{*{20}{c}} 9\\ 4\\ {10} \end{array}} \right],$ then $\left[ {\begin{array}{*{20}{c}} x\\ y\\ z \end{array}} \right]$ is equal to

$\left[ {\begin{array}{*{20}{c}} 1\\ 2\\ 3 \end{array}} \right]$

$\left[ {\begin{array}{*{20}{c}} 3\\ 2\\ 1 \end{array}} \right]$

$\left[ {\begin{array}{*{20}{c}} 2\\ 3\\ 1 \end{array}} \right]$

$\left[ {\begin{array}{*{20}{c}} 2\\ 1\\ 3 \end{array}} \right]$

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JEE MATHEMATICS MCQ: MATRICES

1 Easy

1 of 1

Application +4 | -1

\left[ {\begin{array}{cccccccccccccccccccc} 2&{ - 1}&3\\ 1&3&{ - 1}\\ 3&2&1 \end{array}} \right]\left[ {\begin{array}{cccccccccccccccccccc} x\\ y\\ z \end{array}} \right] = \left[ {\begin{array}{cccccccccccccccccccc} 9\\ 4\\ {10} \end{array}} \right],

then

\left[ {\begin{array}{cccccccccccccccccccc} x\\ y\\ z \end{array}} \right]

is equal to

View answer and explanation

Correct option: C

\left[ {\begin{array}{cccccccccccccccccccc} 1\\ 2\\ 3 \end{array}} \right]

Option C ([1], [2], [3]) is correct because it is the solution to the matrix equation, which can be found by multiplying the inverse of the coefficient matrix by the result matrix.

JEE MATHEMATICS MCQ: MATRICES

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