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JEE CHEMISTRY MCQ: AMINES

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CH3CH2CH2CN→Na+C2H3OHX{\text{C}}{{\text{H}}_3}{\text{C}}{{\text{H}}_2}{\text{C}}{{\text{H}}_2}{\text{CN}}\xrightarrow[{}]{{{\text{Na}} + {{\text{C}}_2}{{\text{H}}_3}{\text{OH}}}}{\text{X}}

The product X\mathrm{X} is
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Correct option: B
CH3CH2CH2CH2NH2\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2
Option B (CH3CH2CH2CH2NH2\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{NH}_2) is correct because the cyanide group is reduced to a primary amine by the reducing agent.

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