JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

1 of 1

Application +4 | -1

\sin \theta+\sin 2 \theta+\sin 3 \theta=\sin \alpha

and

\cos \theta

+\cos 2 \theta+\cos 3 \theta=\cos \alpha

, then

\theta

is equal to

View answer and explanation

Correct option: A

\alpha / 2

Option A (

\alpha / 2

) is correct because dividing the sine equation by the cosine equation results in

\tan 2\theta = \tan \alpha

, which implies

\theta = \alpha / 2

More Questions from TRIGONOMETRY RATIOS

Practice All Chapter MCQs →

\tan \alpha=\frac{p}{q}

\alpha=6 \beta

\alpha

\frac{1}{2}[p \operatorname{cosec} 2 \beta-q \sec 2 \beta]

\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

\triangle A B C

C

{\sin ^6}\,\,\theta + {\cos ^6}\,\,\theta + 3{\sin ^2}\,\,\theta \,\,{\cos ^2}\,\,\theta

\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=