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JEE CHEMISTRY MCQ: REDOX REACTIONS

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Application +4 | -1
The value of 'n' in the reaction Cr2O72−+14H++nFe2+→2Cr3++nFe3++7H2O\mathrm{C}{\mathrm{r}_2}\mathrm{O}_7^{2 - } + 14{\mathrm{H}^ + } + n\mathrm{F}{\mathrm{e}^{2 + }} \to 2\mathrm{C}{\mathrm{r}^{3 + }} + n\mathrm{F}{\mathrm{e}^{3 + }} + 7{\mathrm{H}^2}\mathrm{O} will be
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Correct option: C
6
Option C (6) is correct because balancing the redox reaction shows that 6 moles of Fe2+ are required to react with 1 mole of dichromate.

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