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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
If f(x)f\left( x \right) is defined [− 2,   2]    by    f(x)=4x2−  3x+1\left[ { - \,2,\;\,2} \right]\mathrm{\;}\,\,\mathrm{by\;}\,\,f\left( x \right) = 4{x^2} - \,\,3x + 1 and g(x)=f(−x)  −  f(x)x2+  3g\left( x \right) = \frac{{f\left( { - x} \right)\,\, - \,\,f\left( x \right)}}{{{x^2} + \,\,3}},
then ∫−22  g  (x)dx\int \nolimits_{ - 2}^2 \,\,\mathrm{g}\,\,\left( x \right)dx is equal to
View answer and explanation
Correct option: C
0\mathrm{0}
The correct answer is C (0) because g(x) is an odd function, and the integral of an odd function over a symmetric interval is zero.

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