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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If the sum of first nn terms of an AP is cn2c{n^2}, then the sum of squares of these nn terms is
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Correct option: C
n(4n2βˆ’1)c23\frac{{n\left( {4{n^2} - 1} \right){c^2}}}{3}
Option C is correct because it represents the sum of the squares of the terms of the AP, derived from the given sum of the first n terms.

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