NEET UG CHEMISTRY MCQ: HALOALKANES AND HALO ARENES

1 Hard

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Application +4 | -1

\left({CH}_3\right)_2 {C}={CHCH}_3+{NOBr} \longrightarrow

product the structure of the product is

View answer and explanation

Correct option: B

\left({CH}_3\right)_2 {C}({Br})-{CH}({NO}) {CH}_3

Option B (

\left({CH}_3\right)_2 {C}({Br})-{CH}({NO}) {CH}_3

) is correct because the addition of

NOBr

to the alkene follows the anti-Markovnikov rule, with

Br

adding to the more substituted carbon and

NO

to the less substituted carbon.

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