NEET UG PHYSICS MCQ: GRAVITATION

1 Easy

1 of 1

Application +4 | -1

The diameter of a planet is four times that of the earth. Find the time period of pendulum on the planet, if it is a second pendulum on the earth. Take the mean density of the planet equal to that of the earth.

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Correct option: A

The correct answer is 1 because the time period of a pendulum depends on the length and acceleration due to gravity, which are related to the planet's density and radius.

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If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force

\left( { - K/{r^2}} \right)

the total energy is Suppose the law of gravitational attraction suddenly changes and becomes an inverse cube law i.e.

F \propto \frac{1}{r^3}

, but still remaining a central force. Then Two satellites A and B go round a planet P is circular orbits having radii 16 R and 2 R respectively. If the speed of satellite A is

6\,m{s^{ - 1}}

the speed of the satellite B will be [in m/s] nearly The total energy of satellite moving with an orbital velocity

v

around the earth is Two satellites of same mass are launched in the same orbit of radius

r

around the earth so as to rotate opposite to each other. If they collide inelastically and stick together as wreckage, the total energy of the system just after collision is Statement-1: There is almost no effect of rotation of earth at poles.
Statement-2: Because rotation of earth is about polar axis.