NEET UG PHYSICS MCQ: ELECTROMAGNETIC WAVES

1 Hard

1 of 1

Application +4 | -1

An FM radio station, antenna radiates a power of

10 \mathrm{~kW}

at a wavelength of

3 \mathrm{~m}

. Assume the radiated power is confined to and is uniform over a hemisphere with antenna at its centre.

E_{\max }

at a distance of

10 \mathrm{~km}

from antenna is

View answer and explanation

Correct option: D

0.10 \mathrm{NC}^{-1}

Option D (

0.10 \mathrm{NC}^{-1}

) is correct because the maximum electric field is related to the power and distance by

E_{max} = \sqrt{\frac{2P}{\pi \epsilon_0 c r^2}}

More Questions from ELECTROMAGNETIC WAVES

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{E_X}

{E_R}

{E_M}

60\,\,\frac{V}{m}

{E_1} = {E_{01}}\hat x\cos \left[ {2\pi v\left( {\frac{z}{c} - t} \right)} \right]

{E_2} = {E_{02}}\hat x\cos \left[ {k\left( {2z - ct} \right)} \right]

{\varepsilon _{{r_1}}}

{\varepsilon _{{r_2}}}

E = 50\sin \,(500x - 10 \times {10^{10}}t)\,v/m.

c

\mathrm{\varepsilon }

\mathrm{\mu }

\sqrt {\frac{\mathrm{\mu }}{\mathrm{\varepsilon }}}