JEE PHYSICS MCQ: UNITS & MEASUREMENTS

1 Medium

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Application +4 | -1

Volume of liquid flowing per second through a capillary tube is given by

\mathrm{V}=\frac{\mathrm{K}\left[\mathrm{x}_2-\mathrm{x}_1\right]^4}{\left[\mathrm{y}_2-\mathrm{y}_1\right]}

where

x_1

and

x_2

are inner and outer radii and

y_2

and

y_1

are positions crossed by the liquid. The dimensional formula for

\mathrm{K}

is :-

View answer and explanation

Correct option: D

\mathrm{M}^0 \mathrm{~L}^0 \mathrm{~T}^{-1}

Option D (

\mathrm{M}^0 \mathrm{L}^0 \mathrm{T}^{-1}

) is correct because it is derived from the dimensional analysis of the given equation for the volume flow rate.

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