Skip to main content
Back to SEQUENCE OF SERIES

JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy
1 of 1
Analyzing +4 | -1
The sum of the series

1⋅n+1+2⋅(n−1)+3⋅(n−2)…+n⋅11 \cdot n + 1 + 2 \cdot \left( {n - 1} \right) + 3 \cdot \left( {n - 2} \right) \ldots + n \cdot 1 is
View answer and explanation
Correct option: A
n(n+1)(n+2)6\frac{{n\left( {n + 1} \right)\left( {n + 2} \right)}}{6}
Option A (n(n+1)(n+2)6\frac{{n(n + 1)(n + 2)}}{6}) is correct because it represents the sum of the series obtained by summing the product of terms in the form r(n−r+1)r(n - r + 1).

More Questions from SEQUENCE OF SERIES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.