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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Application +4 | -1
The entropy change associated with the conversion of 1 kg of ice at 273 K to water vapours at 383 K is (Specific heat of water liquid and water vapour are 4.2 kJ K−1 kg−14.2\,kJ\,{K^{ - 1}}\,k{g^{ - 1}} and 20 kJ K−1 kg−120\,kJ\,{K^{ - 1}}\,k{g^{ - 1}}; heat of liquid fusion and vapourisation of water are 334 kJ kg−1334\,kJ\,k{g^{ - 1}}\mathrm{ } and 2491 kJ kg−12491\,kJ\,k{g^{ - 1}} respectively).
(log⁡273=2.436,  log⁡373=2.572,  log⁡383=2.583)(\log 273 = 2.436,\,\,\log 373 = 2.572,\,\,\log 383 = 2.583)
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Correct option: A
9.26 kJ  kg−1 K−19.26\,kJ\,\mathrm{ }\,k{g^{ - 1}}\,{K^{ - 1}}
Option A (9.26 kJ kg−1 K−19.26\,kJ\,k{g^{ - 1}}\,{K^{ - 1}}) is correct because it represents the total entropy change calculated by summing the entropy changes for each phase transition and heating step.

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