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NEET UG PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1
A particle of mass mΒ kgm \mathrm{~kg} is travelling at constant speed vΒ m/sv \mathrm{~m} / \mathrm{s} round a circle of radius rmβ€²r_{m^{\prime}} (a) If v=8v=8 and r=2r=2, find the magnitude of the central acceleration (in m/s2\mathrm{m} / \mathrm{s}^2 ).
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Correct option: A
32
Option A (32) is correct because the centripetal acceleration is calculated using a=v2/ra = v^2/r, where v is the speed and r is the radius.

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