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JEE CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

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Analyzing +4 | -1

{M^{ + 3}}

ion has the electronic configuration as

\left[ {Xe} \right]\,\,5{d^{10}}4{f^{14}}6{s^2},

hence the element

M

belongs to

View answer and explanation

Correct option: B

p-block

Option B (p-block) is correct because after removing three electrons, the electronic configuration ends with 6s² 5d¹⁰ 4f¹⁴ 6p³, indicating that the element M belongs to the p-block.

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