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JEE PHYSICS MCQ: WAVE OPTICS

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Application +4 | -1

If prism angle

\alpha=1^{\circ}, \mu=1.54

, distance between screen and prism (b)

=0.7 \mathrm{~m}

, distance between prism and source

a=0.3 \mathrm{~m}, \lambda=180 \pi \mathrm{nm}

then in Fresnal biprism find the value of

\beta

(fringe width)

View answer and explanation

Correct option: C

10^{-4} \times \pi \mathrm{m}

Option C (

10^{-4} \times \pi \mathrm{~m}

) is correct because it is the fringe width calculated using the Fresnel biprism formula.

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