JEE MATHEMATICS MCQ: PERMUTATIONS

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A man invites 6 non-vegeterian and 5 vegeterian friends for a dinner party. He arrange 6 non-vegeterian friends on one round table and 5 vegeterian friends along another round table. The number of ways this can be done is:

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Correct option: C

2880

Option C (2880) is correct because arranging the non-vegetarians and vegetarians separately on round tables gives (6-1)! * (5-1)! = 2880 ways.

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