JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1

The dimensions of emf in MKS is

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Correct option: D

\left[ {\mathrm{M}{\mathrm{L}^2}{\mathrm{T}^{ - 2}}{\mathrm{Q}^{ - 1}}} \right]

Option D (

\left[ {\mathrm{M}{\mathrm{L}^2}{\mathrm{T}^{ - 2}}{\mathrm{Q}^{ - 1}}} \right]

) is correct because the dimensions of emf are derived from its definition in terms of inductance and current.

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