If $\tan A = \frac{{1 - \cos \,\,B}}{{\sin \,\,B}}$, then

$\tan \,\,2A = {\tan ^2}B + 2\,\,\tan B$

JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

1 Easy

1 of 1

Application +4 | -1

\tan A = \frac{{1 - \cos \,\,B}}{{\sin \,\,B}}

, then

View answer and explanation

Correct option: A

\tan \,\,2A = \tan B

Option A is correct because it correctly uses trigonometric identities to simplify the given equation and derive the relationship between

\tan 2A

and

\tan B

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