$\mathop \smallint \nolimits_1^x \,\,\frac{{\log \,\,\left( {{x^2}} \right)}}{x}\;\,\,dx$ is equal to

$\frac{1}{2}\,\,{(\log \,\,x)^2}$

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1

\int \nolimits_1^x \,\,\frac{{\log \,\,\left( {{x^2}} \right)}}{x}\;\,\,dx

is equal to

View answer and explanation

Correct option: A

{(\log \,\,x)^2}

Option A (

{(\log \,\,x)^2}

) is correct because the integral of the given expression simplifies to this result after substitution.

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