JEE MATHEMATICS MCQ: LIMITS

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Application +4 | -1

f(x)=\left\{\begin{array}{ccc}-2 \sin x & \text { if } & x \leq-\frac{\pi}{2} \\ A \sin x+B & \text { if } & -\frac{\pi}{2} < x < \frac{\pi}{2} \\ \cos x & \text { if } & x \geq \frac{\pi}{2}\end{array}\right.

is a continuous function then

View answer and explanation

Correct option: B

A=-1, B=1

Option B (

A=-1, B=1

) is correct because these values ensure the function is continuous at

x=-\frac{\pi}{2}

and

x=\frac{\pi}{2}

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