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JEE PHYSICS MCQ: WAVE OPTICS

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Application +4 | -1
Maximum intensity in YDSE is I0{I}_0. The intensity at a point on the sereen where the path difference between the two interfering waves is λ3\frac{\lambda}{3} will be;
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Correct option: D
I04\frac{I_0}{4}
Option D (I04\frac{I_0}{4}) is correct because the intensity at a point with a path difference of λ3\frac{\lambda}{3} is I04\frac{I_0}{4}.

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