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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
If y=2x2−1,y = 2{x^2} - 1, then 1x2+12x4+13x6+…∞\frac{1}{{{x^2}}} + \frac{1}{{2{x^4}}} + \frac{1}{{3{x^6}}} + \ldots \infty equals to
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Correct option: A
log⁡e(y+1y−1){\log _e}\left( {\frac{{y + 1}}{{y - 1}}} \right)
Option A (log⁡e(y+1y−1)\log _e\left( {\frac{{y + 1}}{{y - 1}}} \right)) is correct because it is the result of simplifying the given series using logarithmic properties and the given substitution.

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