JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum of first 12 terms of the series

\frac{1^3}{1}+\frac{1^3+2^3}{1+3}+\frac{1^3+2^3+3^3}{1+3+5}+\ldots

n

terms is equal to

View answer and explanation

Correct option: C

\frac{409}{2}

Option C (409/2) is correct because the sum of the first 12 terms of the series is calculated to be 409/2.

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