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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Application +4 | -1

What is the energy

({kJ} / {mol})

associated with the de-excitation of an electron from

{n}=6

to

{n}=2

in

{He}^{+}

ion?

View answer and explanation

Correct option: C

1.16 \times 10^3

Option C (

1.16 \times 10^3

) is correct because it is the energy calculated using the Rydberg formula for the de-excitation of an electron in a

{He}^{+}

ion.

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